Python code to Send email using Amazon Simple Email Service (AWS SES)

 Below is the python code to send email using Amazon Simple Email Service.

import smtplib  

import email.utils

from email.mime.multipart import MIMEMultipart

from email.mime.text import MIMEText

import json

def lambda_handler(event, context):

    print(event)

    SENDER = 'sender_email_id'  

    SENDERNAME = 'sender_name'

    RECIPIENT  = 'recipient_email_id'

    USERNAME_SMTP = "aws_smtp_username"

    PASSWORD_SMTP = "aws_smtp_pd"

    HOST = "Host server name"

    PORT = 587

    SUBJECT = 'Test Email'

    BODY_TEXT = ("This is the test mail\r\n"

                 "This mail was sent for testing purpose "

                 "Kindly ignore this mail."

                )

    msg = MIMEMultipart('alternative')

    msg['Subject'] = SUBJECT

    msg['From'] = email.utils.formataddr((SENDERNAME, SENDER))

    msg['To'] = RECIPIENT

    part1 = MIMEText(BODY_TEXT, 'plain')

    

    msg.attach(part1)

    try:  

        server = smtplib.SMTP(HOST, PORT)

        server.ehlo()

        server.starttls()

        

        server.ehlo()

        server.login(USERNAME_SMTP, PASSWORD_SMTP)

        server.sendmail(SENDER, RECIPIENT, msg.as_string())

        server.close()

    

    except Exception as e:

        print ("Error: ", e)

    else:

        print ("Email sent!")

        return {

            'statusCode': 200,

            'body': json.dumps('Success')

            }

Thanks And Regards

Praveen Kumar Rajendran

praveenkumar558@gmail.com

AWS August 09, 2020